3.4.1 Quantum Mechanical Vt correction

$QMFACTOR_i$ is also a switch.

If $GEOMOD \ne 3$ then,

$E_0 = \dfrac{\hbar^2 \pi^2}{2 m_x \cdot {TFIN}^2} \qquad (3.257)$

$E_0^{'} = \dfrac{\hbar^2 \pi^2}{2 m_x^{'} \cdot {TFIN}^2} \qquad (3.258)$

$E_1 = 4 E_0 \qquad (3.259)$

$E_1^{'} = 4 E_0^{'} \qquad (3.260)$

$\gamma = 1 + exp \Big( \dfrac{E_0 - E_1}{kT} \Big) + \dfrac{g^{'} \cdot m_d^{'}}{g \cdot m_d} \cdot \Bigg[ exp \Big( \dfrac{E_0 - E_0^{'}}{kT} \Big) + exp \Big( \dfrac{E_0 - E_1^{'}}{kT} \Big) \Bigg] \qquad (3.261)$

$\Delta V_{t, QM} = QMFACTOR_i \cdot \Bigg[ \dfrac{E_0}{q} - \dfrac{kT}{q} ln \Big( \dfrac{g \cdot m_d}{\pi \hbar^2 N_c} \cdot \dfrac{kT}{TFIN} \cdot \gamma \Big) \Bigg] \qquad (3.262)$

If $GEOMOD = 3$ then,

$E_{0,QM} = \dfrac{\hbar^2 (2.4048)^2 }{2 m_x \cdot R^2} \qquad (3.263)$

$\Delta V_{t, QM} = QMFACTOR_i \cdot \dfrac{E_{0,QM}}{q} \qquad (3.264)$